Eq

Eq()

An equal relation between two objects, the left-hand side and the right-hand side.

The left-hand side may be a Function or a SparseFunction. The right-hand side may be any arbitrary expressions with numbers, Dimensions, Constants, Functions and SparseFunctions as operands.

Parameters

Name	Type	Description	Default
lhs	Function or SparseFunction	The left-hand side.	required
rhs	expr - like	The right-hand side.	0
subdomain	SubDomain	To restrict the computation of the Eq to a particular sub-region in the computational domain.	None
coefficients	Substitutions	Can be used to replace symbolic finite difference weights with user defined weights.	None
implicit_dims	Dimension or list of Dimension	An ordered list of Dimensions that do not explicitly appear in either the left-hand side or in the right-hand side, but that should be honored when constructing an Operator.	None

Examples

>>> from devito import Grid, Function, Eq
>>> grid = Grid(shape=(4, 4))
>>> f = Function(name='f', grid=grid)
>>> Eq(f, f + 1)
Eq(f(x, y), f(x, y) + 1)

Any SymPy expressions may be used in the right-hand side.

>>> from devito import sin
>>> Eq(f, sin(f.dx)**2)
Eq(f(x, y), sin(Derivative(f(x, y), x))**2)

Notes

An Eq can be thought of as an assignment in an imperative programming language (e.g., a[i] = b[i]*c).

Attributes

Name	Description
is_Reduction	bool(x) -> bool
subdomain	The SubDomain in which the Eq is defined.

Methods

Name	Description
func	Reconstruct self via self.__class__(*args, **kwargs) using

func

func(*args, **kwargs)

Reconstruct self via self.__class__(*args, **kwargs) using self’s __rargs__ and __rkwargs__ if and where *args and **kwargs lack entries.

Examples

Given

class Foo:
    __rargs__ = ('a', 'b')
    __rkwargs__ = ('c',)
    def __init__(self, a, b, c=4):
        self.a = a
        self.b = b
        self.c = c

a = foo(3, 5)`

Then:

* `a._rebuild() -> x(3, 5, 4)` (i.e., copy of `a`).
* `a._rebuild(4) -> x(4, 5, 4)`
* `a._rebuild(4, 7) -> x(4, 7, 4)`
* `a._rebuild(c=5) -> x(3, 5, 5)`
* `a._rebuild(1, c=7) -> x(1, 5, 7)`